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<blockquote data-quote="Brian Murphy" data-source="post: 4922" data-attributes="member: 1805">I&#039;ve been reading a few threads on subs and have some questions. On one thread on subs Phil Graham was explaining V_rms=sq.rt of P_in*R_dc for the power input to a driver.&nbsp; I get that. However some speakers like the UCS1 give &quot;Program&quot;(2400W) and &quot;Peak&quot;(1200W) so to use the above formula shouldn&#039;t I use .707*Peak in the equation?So: Sq.Rt of [(1200W*.707)*8(ohms)]= 82.38 V_rms. If I use the equation for &quot;Power&quot;:&nbsp; P= (E*E/R)*1.414 and you get 1200W peak give or take calculator rounding so this would seem logical.OK so if you now look at Amp specs and they don&#039;t give a V_rms spec would one use (.707*Slew rate) as V-rms, since slew rate is the max change in output voltage? Or am I off base? If so, what spec would be the best to covert or arrive at V_rms if it&#039;s not given?Should one match the V_rms output of the amp to the V_rms of the speaker or would it be better to convert both calculations to Peak?Thanks,Murph..............</blockquote>

[QUOTE="Brian Murphy, post: 4922, member: 1805"] I've been reading a few threads on subs and have some questions. On one thread on subs Phil Graham was explaining V_rms=sq.rt of P_in*R_dc for the power input to a driver. I get that. However some speakers like the UCS1 give "Program"(2400W) and "Peak"(1200W) so to use the above formula shouldn't I use .707*Peak in the equation? So: Sq.Rt of [(1200W*.707)*8(ohms)]= 82.38 V_rms. If I use the equation for "Power": P= (E*E/R)*1.414 and you get 1200W peak give or take calculator rounding so this would seem logical. OK so if you now look at Amp specs and they don't give a V_rms spec would one use (.707*Slew rate) as V-rms, since slew rate is the max change in output voltage? Or am I off base? If so, what spec would be the best to covert or arrive at V_rms if it's not given? Should one match the V_rms output of the amp to the V_rms of the speaker or would it be better to convert both calculations to Peak? Thanks, Murph.............. [/QUOTE]

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