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Re: 5K$ anyone?Math retard here but I'm trying to learn.So 45 db gain (142-97).then 10log(1w:xw)=45then log(1w:xw)=4.5then log(x)=4.5then x = 10^4.5then x = 31,622Am I way off?or10log (1w:4949w)=x10log (4949)=x10(3.69)=xx=36.9dbso 97db1w/1m plus 36.9db gain for 4949 watts comes out to 133.9db calculated max output.Anyway, I am a math loser and need education on something even this elementary. What am I missing?Thanks,Loren
Re: 5K$ anyone?
Math retard here but I'm trying to learn.
So 45 db gain (142-97).
then 10log(1w:xw)=45
then log(1w:xw)=4.5
then log(x)=4.5
then x = 10^4.5
then x = 31,622
Am I way off?
or
10log (1w:4949w)=x
10log (4949)=x
10(3.69)=x
x=36.9db
so 97db1w/1m plus 36.9db gain for 4949 watts comes out to 133.9db calculated max output.
Anyway, I am a math loser and need education on something even this elementary. What am I missing?
Thanks,
Loren