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DSP Filters and slopes?
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<blockquote data-quote="Charlie Hughes" data-source="post: 27340" data-attributes="member: 474"><p>Re: DSP Filters and slopes?</p><p></p><p>Hi Douglas,</p><p>Take a look at Phil's very good explanation. Even is a filter with 180° phase shift was used to cancel a portion of the bandwidth of a signal, this filter must still have a transition region (roll-off) between its pass band and its stop band.</p><p></p><p>Physics dictates that the more narrow something is in the frequency domain, the more broad it must be in the time domain (and vice-versa). This means that a true brick wall filter cut off (0 Hz transition region), about which you originally inquired, would require infinite time to process. Classical uncertainty principle at work; deltaT = 1 / deltaF.</p></blockquote><p></p>
[QUOTE="Charlie Hughes, post: 27340, member: 474"] Re: DSP Filters and slopes? Hi Douglas, Take a look at Phil's very good explanation. Even is a filter with 180° phase shift was used to cancel a portion of the bandwidth of a signal, this filter must still have a transition region (roll-off) between its pass band and its stop band. Physics dictates that the more narrow something is in the frequency domain, the more broad it must be in the time domain (and vice-versa). This means that a true brick wall filter cut off (0 Hz transition region), about which you originally inquired, would require infinite time to process. Classical uncertainty principle at work; deltaT = 1 / deltaF. [/QUOTE]
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