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Junior Varsity
Help me understand the concept of speaker “throw” please.
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<blockquote data-quote="Perry Wright" data-source="post: 218143" data-attributes="member: 13023"><p>Throw</p><p></p><p>Yes, I know that I’m late to the party, so no comments about that …..</p><p></p><p>But for anyone stumbling onto this discussion, I want to clear up a couple of things. </p><p></p><ul> <li data-xf-list-type="ul">First - the "throw" does indeed describe the distance sound will project. A narrower pattern will inherently project farther because it spreads out less. </li> <li data-xf-list-type="ul">Second - the "inverse square" law is misleading a lot of people into thinking, incorrectly, that coverage angle does not matter. It actually matters tremendously. When you say that the sound level decreases by 6dB per double the distance, without specifying the area, the angle, and the distance, it means nothing. If the area is one foot square, and you move out to where the area is two feet square, and then move to where it is four feet square, each step will indeed be double the distance. But it is obvious that, if the angle of spread is narrower, the distances will be substantially larger. If the sound is a "plane wave" like inside a pipe, the sound loss would be almost zero over quite a long distance. </li> <li data-xf-list-type="ul">Some speakers are referred to as a "point source". This is impossible. A typical loudspeaker has a coverage pattern of 90° x 40°, not omnidirectional at all. A column speaker may have a pattern of 100° x 70°. Slightly wider horizontal, and slightly narrower vertical than a single driver (about 90° conical). The problem is, the row of small, inefficient little drivers has NO component that is capable of projecting sound to the back of an auditorium, 50 to 100 feet away. And in actual listening tests, the high frequencies are extremely beamy, covering very little off axis. </li> </ul></blockquote><p></p>
[QUOTE="Perry Wright, post: 218143, member: 13023"] Throw Yes, I know that I’m late to the party, so no comments about that ….. But for anyone stumbling onto this discussion, I want to clear up a couple of things. [LIST] [*]First - the "throw" does indeed describe the distance sound will project. A narrower pattern will inherently project farther because it spreads out less. [*]Second - the "inverse square" law is misleading a lot of people into thinking, incorrectly, that coverage angle does not matter. It actually matters tremendously. When you say that the sound level decreases by 6dB per double the distance, without specifying the area, the angle, and the distance, it means nothing. If the area is one foot square, and you move out to where the area is two feet square, and then move to where it is four feet square, each step will indeed be double the distance. But it is obvious that, if the angle of spread is narrower, the distances will be substantially larger. If the sound is a "plane wave" like inside a pipe, the sound loss would be almost zero over quite a long distance. [*]Some speakers are referred to as a "point source". This is impossible. A typical loudspeaker has a coverage pattern of 90° x 40°, not omnidirectional at all. A column speaker may have a pattern of 100° x 70°. Slightly wider horizontal, and slightly narrower vertical than a single driver (about 90° conical). The problem is, the row of small, inefficient little drivers has NO component that is capable of projecting sound to the back of an auditorium, 50 to 100 feet away. And in actual listening tests, the high frequencies are extremely beamy, covering very little off axis. [/LIST] [/QUOTE]
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Help me understand the concept of speaker “throw” please.
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