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More to a measurement then the transfer function?
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<blockquote data-quote="Ivan Beaver" data-source="post: 148934" data-attributes="member: 30"><p>Re: More to a measurement then the transfer function?</p><p></p><p></p><p>The transfer function gives some information, but no where near the "whole picture".</p><p></p><p>With a normal loudspeakers with separated drivers, changing the crossover point will change the polar pattern etc.</p><p></p><p>When looking at just a DSP, how would you get a second arrival-unless you are doing multipath and have a different delay in the paths?</p><p></p><p>A second arrival may or may not appear on the transfer function.</p><p></p><p>It will depend on the size of the time window you are using the amount of time between the 1st and 2nd signal arrivals.</p><p></p><p>If the 2nd arrival fits in the time window, then you will see it as a classic combfilter and a series of notches in the response that are equally spaced in FREQ, On a linear scale they will look like the teeth on a comb (hence the name), but on a linear scale they will get closer and closer together as the freq increases</p><p></p><p>So-as usual-the answer is "it depends".</p></blockquote><p></p>
[QUOTE="Ivan Beaver, post: 148934, member: 30"] Re: More to a measurement then the transfer function? The transfer function gives some information, but no where near the "whole picture". With a normal loudspeakers with separated drivers, changing the crossover point will change the polar pattern etc. When looking at just a DSP, how would you get a second arrival-unless you are doing multipath and have a different delay in the paths? A second arrival may or may not appear on the transfer function. It will depend on the size of the time window you are using the amount of time between the 1st and 2nd signal arrivals. If the 2nd arrival fits in the time window, then you will see it as a classic combfilter and a series of notches in the response that are equally spaced in FREQ, On a linear scale they will look like the teeth on a comb (hence the name), but on a linear scale they will get closer and closer together as the freq increases So-as usual-the answer is "it depends". [/QUOTE]
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More to a measurement then the transfer function?
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