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Junior Varsity
Passive Crossovers/ Zobel etc..
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<blockquote data-quote="David Morison" data-source="post: 218038" data-attributes="member: 2076"><p>[ATTACH=full]209827[/ATTACH]</p><p></p><p>OK, so Green is the response of the filter* without R2, showing a bit of a peak (ie High Q) before rolling off.</p><p>Red is with R2, showing a more moderate response.</p><p></p><p>* Note that this assumes a perfectly straight 8Ω impedance - real drivers will show deviation from this.</p><p></p><p>Art, I don't think your low impedance at high frequencies will be a problem because the combined block of C1+R2+Driver is in series after L1, so the high impedance of the inductor at higher frequencies will dominate. With 100V of pink noise applied, R2 only dissipates a couple of watts (again, assuming a flat 8Ω driver):</p><p></p><p>[ATTACH=full]209829[/ATTACH]</p></blockquote><p></p>
[QUOTE="David Morison, post: 218038, member: 2076"] [ATTACH type="full" alt="1694332278045.png"]209827[/ATTACH] OK, so Green is the response of the filter* without R2, showing a bit of a peak (ie High Q) before rolling off. Red is with R2, showing a more moderate response. * Note that this assumes a perfectly straight 8Ω impedance - real drivers will show deviation from this. Art, I don't think your low impedance at high frequencies will be a problem because the combined block of C1+R2+Driver is in series after L1, so the high impedance of the inductor at higher frequencies will dominate. With 100V of pink noise applied, R2 only dissipates a couple of watts (again, assuming a flat 8Ω driver): [ATTACH type="full"]209829[/ATTACH] [/QUOTE]
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