Reply to thread

Message

<blockquote data-quote="Jay Barracato" data-source="post: 7012" data-attributes="member: 24">At some point I was told that the optimum angle for front lighting was 45 degrees to the performers. So what does this mean about mounting the lights, especially if you have a portable rig of trees or truss.For ease of calculation let&#039;s imagine a 6 foot tall performer standing on the stage. Since both legs of a 45-45-90 right triangle are the same length, there is a point on the floor 6 feet behind the performer that creates a 45 degree angle.Using that point as a vertex, a lighting bar 10 feet in front of the performer would be 16 feet from that vertex. That means the lights would have to be 16 feet above the plane the performer is standing on to achieve the 45 degree angle.If the performer is standing on a stage and the lighting trees are on the floor, simply add the height of the stage.I.e. The performer is on a 4 foot high stage, and the lights are 12 feet in front of where the performer stands, the lights would have to be 12+6+4 = 22 feet high to get a 45 degree angle between the performer and the lights.If the performer is on a 2 foot high stage, and the truss is 6 feet in front of the performer, the lights should be 6+6+2 = 14 feet from the floor.There will be a quiz next time, and no, I don&#039;t grade on a curve, I grade on a surface area...</blockquote>

[QUOTE="Jay Barracato, post: 7012, member: 24"] At some point I was told that the optimum angle for front lighting was 45 degrees to the performers. So what does this mean about mounting the lights, especially if you have a portable rig of trees or truss. For ease of calculation let's imagine a 6 foot tall performer standing on the stage. Since both legs of a 45-45-90 right triangle are the same length, there is a point on the floor 6 feet behind the performer that creates a 45 degree angle. Using that point as a vertex, a lighting bar 10 feet in front of the performer would be 16 feet from that vertex. That means the lights would have to be 16 feet above the plane the performer is standing on to achieve the 45 degree angle. If the performer is standing on a stage and the lighting trees are on the floor, simply add the height of the stage. I.e. The performer is on a 4 foot high stage, and the lights are 12 feet in front of where the performer stands, the lights would have to be 12+6+4 = 22 feet high to get a 45 degree angle between the performer and the lights. If the performer is on a 2 foot high stage, and the truss is 6 feet in front of the performer, the lights should be 6+6+2 = 14 feet from the floor. There will be a quiz next time, and no, I don't grade on a curve, I grade on a surface area... [/QUOTE]

Verification