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<blockquote data-quote="Ivan Beaver" data-source="post: 148692" data-attributes="member: 30">Re: Speaker protectionActually it was NOT &quot;getting power meant for 2&quot;.The ONLY thing you can apply is voltage-NOT wattage.&nbsp; The wattage is the RESULT of the voltage across a certain impedance load.Let&#039;s look at your &quot;numbers&quot;.&nbsp; You say 1000 watts peak for 2 drivers that are 8 ohms each-so that is a 8 ohm load and 250watts continuous per driver or 500 watts @ 4 ohms total cabinet rating.IF this seems wrong-then maybe I am not understanding your &quot;specs&quot;.But follow along anyway for an example.So for a wattage of 500 watts@ 4 ohms, that is 44.7 volts.So if each driver is 250 watts @ 8 ohms, that is ALSO 44.7 volts.So if you were only driving one driver with 44.7V, then you ARE NOT applying any more power than the speaker is rated at.HOWEVER-HERE is the problem with only driving one driver in a cabinet.&nbsp; First of all you are not getting the combined output of BOTH drivers when being driven .&nbsp; This results in a 6dB lower output.BUT-it gets worse.&nbsp; Since the other driver is not being driven, it will actually be CANCELLING the sound from the driven loudspeaker.&nbsp; How much?&nbsp; It depends on the design and construction of the cabinet.&nbsp; Are the drivers sharing a common chamber? or are they in separate chambers?&nbsp; In the first case you will be detuning the&nbsp; overall response.&nbsp; In the second case you will have notches in the response-making&nbsp; it quieter at some freq.But the POWER will not be changing (yes there will be some slight differences in impedance-but I am ignoring that for now, for the sake of simplicity).But with the second driver not being driven, the system is likely to be pushed harder-which will increase the average VOLTAGE going to the speaker-which results in more power being dissipated and burning it up.So if you are NOT driving the power for 2 into a single driver.&nbsp; They both would be getting the same voltage.I hope this makes sense and helps.</blockquote>

[QUOTE="Ivan Beaver, post: 148692, member: 30"] Re: Speaker protection Actually it was NOT "getting power meant for 2". The ONLY thing you can apply is voltage-NOT wattage. The wattage is the RESULT of the voltage across a certain impedance load. Let's look at your "numbers". You say 1000 watts peak for 2 drivers that are 8 ohms each-so that is a 8 ohm load and 250watts continuous per driver or 500 watts @ 4 ohms total cabinet rating. IF this seems wrong-then maybe I am not understanding your "specs". But follow along anyway for an example. So for a wattage of 500 watts@ 4 ohms, that is 44.7 volts. So if each driver is 250 watts @ 8 ohms, that is ALSO 44.7 volts. So if you were only driving one driver with 44.7V, then you ARE NOT applying any more power than the speaker is rated at. HOWEVER-HERE is the problem with only driving one driver in a cabinet. First of all you are not getting the combined output of BOTH drivers when being driven . This results in a 6dB lower output. BUT-it gets worse. Since the other driver is not being driven, it will actually be CANCELLING the sound from the driven loudspeaker. How much? It depends on the design and construction of the cabinet. Are the drivers sharing a common chamber? or are they in separate chambers? In the first case you will be detuning the overall response. In the second case you will have notches in the response-making it quieter at some freq. But the POWER will not be changing (yes there will be some slight differences in impedance-but I am ignoring that for now, for the sake of simplicity). But with the second driver not being driven, the system is likely to be pushed harder-which will increase the average VOLTAGE going to the speaker-which results in more power being dissipated and burning it up. So if you are NOT driving the power for 2 into a single driver. They both would be getting the same voltage. I hope this makes sense and helps. [/QUOTE]

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