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Virtual SMAART training: Tell the crossover frequency and type
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<blockquote data-quote="Peter Morris" data-source="post: 39899" data-attributes="member: 652"><p>Re: Virtual SMAART training: Explanation Slide 3</p><p></p><p></p><p></p><p></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"><span style="font-family: 'Arial'">Hi Phil,</span></span></span></span></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"><span style="font-family: 'Arial'"></span></span></span></span></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"><span style="font-family: 'Arial'">What I don't understand is there is a step in the phase response of 180 degrees from +90 to -90 at the crossover (2K). There also seems to be a corresponding dip in the amplitude response where things aren’t summing too well. </span></span></span></span></p><p> <span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"></span></span></span></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"><span style="font-family: 'Arial'">I would have assumed that QSC would have matched the phase and required delay nicely through the crossover. The apparent difference in arrival times of the HF and LF drivers seemed too much if it was related to your measurement being a little off axis.</span></span></span></span></p><p> <span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"></span></span></span></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"><span style="font-family: 'Arial'">I must confess I wondered if the polarity of the HF driver was wrong, but it seemed unlikely on both boxes. I also wondered if it was a QSC K series that someone had reversed the HF driver polarity as has been discussed on some websites. </span></span></span></span></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"><span style="font-family: 'Arial'"></span></span></span></span></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"><span style="font-family: 'Arial'">Peter</span></span></span></span></p><p><span style="font-family: 'Times New Roman'"><span style="font-size: 12px"><span style="color: #000000"></span></span></span></p></blockquote><p></p>
[QUOTE="Peter Morris, post: 39899, member: 652"] Re: Virtual SMAART training: Explanation Slide 3 [FONT=Times New Roman][SIZE=3][COLOR=#000000][FONT=Arial]Hi Phil, What I don't understand is there is a step in the phase response of 180 degrees from +90 to -90 at the crossover (2K). There also seems to be a corresponding dip in the amplitude response where things aren’t summing too well. [/FONT] [FONT=Arial] [/FONT] [FONT=Arial]I would have assumed that QSC would have matched the phase and required delay nicely through the crossover. The apparent difference in arrival times of the HF and LF drivers seemed too much if it was related to your measurement being a little off axis.[/FONT] [FONT=Arial] [/FONT] [FONT=Arial]I must confess I wondered if the polarity of the HF driver was wrong, but it seemed unlikely on both boxes. I also wondered if it was a QSC K series that someone had reversed the HF driver polarity as has been discussed on some websites. Peter[/FONT] [/COLOR][/SIZE][/FONT] [/QUOTE]
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