Re: Educate me: AES cabling
And as long as the cable is electrically short, the accumulated capacitance is immaterial? I'm fine with that part.
To the contrary, it is with short, mismatched lines that we are typically concerned with cable capacitance. This is the "long mic cable" case where the -3dB frequency is 1 / (2 * pi * R * C) where R is the parallel combination of the source and load resistances and C is the total cable capacitance.
But it sounded to me like Frank was alleging that an /otherwise significant/ parallel capacitance /stopped being significant/ if you properly terminated an otherwise open cable run.
This is indeed what I was alleging. In a matched-termination transmission line the distributed capacitance is cancelled by the distributed inductance and so the capacitance, in itself, does not matter. As Rob pointed out, the frequency limit for a given length of transmission line is typically governed by loss, which, in other than air- or vacuum-insulated lines, occurs mainly in the dielectric. Another consideration in broadband use might be dispersion, in which different frequencies have different velocities, which smears pulses. I'm not enough of a long distance data transmission guy to know, off hand, under what circumstances this becomes a problem.
With respect to what constitutes a "short" line, the lambda/20 figure I gave is conservative and will work in almost all situations -- better safe than sorry. In many circumstances we might get away with using a lambda/4 piece of the "wrong" cable but in RF work lambda/4 is huge. It's the length of a 1/4 wave antenna, or a 1/4 wave stub, for example.
On bandwidth required for binary data transmission, depending on just how the signal is detected at the receiving end, we might want to look at the edge rate (rise and fall times) rather than clock speed. This is true for much of digital hardware design.
Hope I've managed to communicate, at least a little. --Frank