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<blockquote data-quote="Rob Timmerman" data-source="post: 137461" data-attributes="member: 172"><p>Re: Sound & Stage Power</p><p></p><p></p><p></p><p>Not quite. If you have 3x 2kW loads that you can connect either line-neutral or line-line on a 3-phase circuit, the current in each phase is the same. </p><p></p><p>When the loads are connected line-neutral, you are loading each phase with 2kW (~16A at 120V), and the neutral provides the return path. Because the current flowing in the neutral from each phase is also ~16A, but the phases are 120 degrees apart, the sum of the current in the neutral is zero (16A at 0 degrees plus 16A at 120 degrees plus 16A at 240 degrees). (This assumes resisitive loads)</p><p></p><p>When the loads are connected line-line, you are still loading each phase with 2kW (~10A at 208V), but the adjacent phase now provides the return path. When you actually work out the values for the line currents, you find that they are identical for both Y and delta connected loads.</p><p></p><p>In short, TANSTAAFL</p></blockquote><p></p>
[QUOTE="Rob Timmerman, post: 137461, member: 172"] Re: Sound & Stage Power Not quite. If you have 3x 2kW loads that you can connect either line-neutral or line-line on a 3-phase circuit, the current in each phase is the same. When the loads are connected line-neutral, you are loading each phase with 2kW (~16A at 120V), and the neutral provides the return path. Because the current flowing in the neutral from each phase is also ~16A, but the phases are 120 degrees apart, the sum of the current in the neutral is zero (16A at 0 degrees plus 16A at 120 degrees plus 16A at 240 degrees). (This assumes resisitive loads) When the loads are connected line-line, you are still loading each phase with 2kW (~10A at 208V), but the adjacent phase now provides the return path. When you actually work out the values for the line currents, you find that they are identical for both Y and delta connected loads. In short, TANSTAAFL [/QUOTE]
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